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In the reaction N_2 + 3H_2 iff 2NH_3 + x kCal, one mole of N_2 reacts with 3 moles of H_2 at equilibrium.. Then the valueofalpha( degree of dissociation ) is approximately ………. . P is the pressure at equilibrium |
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Answer» `(p(sqrt(27K_p)))/(8) ` `{:( , N_(2) , + , 3 H_(2) hArr 2 NH_(3)) , ("Initial moles" , 1 ,, 3 ""0), ("Moles of EQUILIBRIUM" , (1- alpha) ,, (3 - 3 alpha) "" 2alpha):}` `K_(P) = ((P_(NH_(3)))^(2))/((P_(N_(2))) (P_(H_(2)))^(3)) = (((2X)/(4 - 2alpha))^(2)p^(2))/([(( 1- alpha)/(4 - alpha))^(P)][(3(1 - a)P)/(4 - alpha)]^(3)) = (4 alpha^(2) p^(2))/((4 - 2 alpha)^(2)) xx ((4 - alpha)^(4))/((1 - alpha)^(4) P^(4) 27)` `K_(P) = (4 alpha^(2) (4 - 2 alpha)^(2))/(27 (1- alpha)^(4) P^(2)) = (16 alpha^(2) (2 - alpha)^(2))/(27 P^(2) (1 - alpha)^(4)) = (16 alpha^(2) (2)^(2))/(27 P^(2) (1)^(4)) { because alpha lt lt 1}` `implies sqrt((27 K_(P)^(2))/(64))= alpha implies alpha = (P sqrt(27 K_(P)))/(8)` |
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