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In the reaction: `Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`, the equivalent weight of `Na_(2)S_(2)O_(3)` will be: (M= molecular weight of `Na_(2)S_(2)O_(3))`A. `(M)/(4)`B. `(M)/(8)`C. `(M)/(1)`D. `(M)/(2)` |
Answer» Correct Answer - b |
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