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In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO_(2) is ___ |
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Answer» Solution :`2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+)to2Mn^(2+)+10CO_(2)+8H_(2)O` `therefore5C_(2)O_(4)^(-2)to10CO_(2)+10bare` Total 10 ELECTRONS for 10 `CO_(2)` molecules so 1 ELECTRON per `CO_(2)` MOLECULE. |
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