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In the reaction of Zn with HCl, 140.15 g of ZnCl2 was actually formed, although the theoretical yield was 143 g. What was the percent yield? |
Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/98-342802" style="font-weight:bold;" target="_blank" title="Click to know more about 98">98</a>% yield.</p><p><strong>Explanation:</strong></p><p>Zn+2HCl _ H2+ZnCl2</p><p> 140.15g</p><p></p><p>140.15÷143g =98%</p></body></html> | |