1.

In the reaction of Zn with HCl, 140.15 g of ZnCl2 was actually formed, although the theoretical yield was 143 g. What was the percent yield?

Answer»

Answer:

98% yield.

Explanation:

Zn+2HCl _ H2+ZnCl2

140.15g

140.15÷143g =98%



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