In the redox reactin xKMnO_(4)+NH_(3)rarryKNO_(3)+MnO_(2)+KOH+H_(2)O

1.	In the redox reactin xKMnO_(4)+NH_(3)rarryKNO_(3)+MnO_(2)+KOH+H_(2)O
Answer» x=4,y=6 x=3,y=8 x=8,y=6 x=8,y=3 Solution :`MnO_(4)^(-)+2H_(2)O+3e^(-)rarrMnO_(2)+4OH^(-)XX8` `NH_(3)+9OH^(-)rarrNO_(3)^(-)+6H_(2)O+8e^(-)[XX` `8MnO_(4)^(-)+3NH_(3)rarr8MnO_(2)+3NO_(3)^(-)+5OH^(-)+2H_(2)O` or `8KMnO_(4)+3 NH_(3)rarr8MnO_(2)+3KNO_(3)+5KOH+2H_(2)O` THUS coefficient of `KmnO_(4)=8` and that of `KNO_(3)=3`

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