In the relation `( dy)/( dt) = 2 omega sin ( omega t + phi_(0))`, the dimensional formula for ` omega t + phi_(0)` isA. `MLT`B. `MLT^(0)`C. `ML^(0) T^(0)`D. `M^(0) L^(0) T^(0)`

In the relation `( dy)/( dt) = 2 omega sin ( omega t + phi_(0))`, the

1.	In the relation `( dy)/( dt) = 2 omega sin ( omega t + phi_(0))`, the dimensional formula for ` omega t + phi_(0)` isA. `MLT`B. `MLT^(0)`C. `ML^(0) T^(0)`D. `M^(0) L^(0) T^(0)`
Answer» Correct Answer - D Here `( omega t + phi_(0))` is dimensionless because it is argument of a trigonometric function.

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In the relation `( dy)/( dt) = 2 omega sin ( omega t + phi_(0))`, the dimensional formula for ` omega t + phi_(0)` isA. `MLT`B. `MLT^(0)`C. `ML^(0) T^(0)`D. `M^(0) L^(0) T^(0)`

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