InterviewSolution
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InterviewSolution
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In the relation ` y = r sin ( omega t - kx)`, the dimensions of `omega//k` areA. `[M^(0) L^(0) T^(0)]`B. `[M^(0) L^(1) T^(-1)]`C. `[M^(0) L^(0) T^(1)]`D. `[M^(0) L^(1) T^(0)]` |
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Answer» Correct Answer - B `y = r sin ( omega t - kx)` Here `omega t = angle rArr omega = (1)/(T) = T^(-1)` Similarly , `kx = angle rArr K = (1)/(x) = L^(-1)` :. (omega)/(k) = (T^(-1))/(L^(-1)) = LT^(-1)` Or simply `omega//k` represents wave velocity. `(omega)/(k) = ( 2 pi f)/( 2 pi//f) = f lambda = v` , where f is frequency. |
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