In the ring test of NO_(3)^(-)ion,Fe^(2+) ion reduces nitrate ion to nitric oxide, which combines with Fe^(2+) (aq) ion to form brown complex. Write the reactions involved in the formation of brown ring.

In the ring test of NO_(3)^(-)ion,Fe^(2+) ion reduces nitrate ion to n

1.	In the ring test of NO_(3)^(-)ion,Fe^(2+) ion reduces nitrate ion to nitric oxide, which combines with Fe^(2+) (aq) ion to form brown complex. Write the reactions involved in the formation of brown ring.
Answer» Solution :`underset("Nitrate ion")NO_(3)^(-)(aq)+3Fe^(2+)(aq)+4H^(+)(aq)tounderset("NITRIC axide")(NO(g))+3Fe^(3+)(aq)+3H_(2)O(l)` `[Fe(H_(2)O)_(6)]^(2+)+NO(g)tounderset("Pentaaquanitrosnium IORN (I) (Brown complex)")([Fe(H_(2)O)_(5)NO]^(2+)+H_(2)O`