1.

In the section `:Na_(2)S_(2)O_(3)+4Cl_(2)+5H_(2)O rarr Na_(2)SO_(4)+H_(2)SO_(4)+8HCl`. the equivalent weight of `Na_(2)S_(2)O_(3)` will be : `(M=` molecular weight of `Na_(2)S_(2)O_(3)`)A. `M//4`B. `M//8`C. `M//1`D. `M//2`

Answer» Correct Answer - 2
`Na_(2)overset(+2)(S)_(2)o_(3)rarr Na_(2)overset(+6)(S)O_(4)`
the total change in oxidation number `=4xx2=8`
`:. " "E_(Na_(2)S_(2)O_(3))=(mol.wt.)/(V.f)=(M)/(8)`


Discussion

No Comment Found

Related InterviewSolutions