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| 1. |
In the series circuit shown in figure, for series resonance, the value of the coupling coefficient, K will be |
| Answer» Mutual inductance wm = ωk L1L2 m = k. 2. 8j2 = 4k. j Z = 20 - j10 + j2 + j6 + 2.4kj - 2j + 8kj = 0 at resonance -2 = -8k k = 1/4 0.25 . | |