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In the shown diagram two point masses m are joined by a massless rod of length 5.5m. The lower end of the mass sytem is dragged with constant velocity `V_(0)` rightwards the magnitude of velocity of centre of mass when `theta=37^(0)`, will beA. `(5v_(0))/(6)`B. `2v_(0)`C. `v_(0)sqrt(2)`D. `(6v_(0))/(5)` |
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Answer» Correct Answer - A `x^(2)+y^(2)=l^(2)` `(dy)/(dt)=-(x)/(y)((dx)/(dt))` if `theta=37^(@)` `(dy)/(dt)=-(x)/(y)(dx)/(dt)=-(4)/(3)v_(@)` `vecv_(cm)=(mv_(@)hati-m(4v_(@))/(3)haty)/(2m)` `|vecV_(cm)|=(5v_(@))/(6)` |
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