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In the shown in the figure `AC` and `BD` are straight lines and `CED` and `AFB` are semicircular with radii `r` and `4r`, respectively. The centre setip is lying in the same plane. If `i` is current entering at `A` what fraction of `i` will flow in the `ACEDB` such that resultant magnetic field at `O` is zero. A. `I//5`B. `4I//5`C. `3I//5`D. no current through bigger semicircular part. |
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Answer» If `I_(1)` is current in `ACDB` then `(mu_(0))/(4)*(i_(1))/(r )=(mu_(0))/(4)*(i_(2))/(4r)rArr(i_(1))/(i_(2))=(1)/(4)` `i_(1)=(1)/(5)xxi=(i)/(5)` |
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