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InterviewSolution
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In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:A. `(5)/(27)`B. `(3)/(23)`C. `(7)/(29)`D. `(9)/(31)` |
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Answer» Correct Answer - A `(1)/(lambda)=R[(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]` For longest wavelelngth model states that an atom is a sphere of Lyman series `n_(1)=1 and n_(2)=2` For longest wavelength of Balmer series `n_(1)2 and n_(2)=3` `" " So (lambda_("Lyman"))/(lambda_("Balmer"))=(5)/(27)` |
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