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InterviewSolution
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In the synthesis of ammonia `N_(2)(g)+3H_(2)hArr2NH_(3)(g)` If the quantity of `N_(2)` reacted is `700mL`, the quantity of `H_(2)` and `NH_(3)` would beA. 300 mL `H_(2)` and 200 mL `NH_(3)`B. 300 mL `H_(2)` and 300 mL `NH_(3)`C. 300 mL `H_(2)` and 100 mL `NH_(3)`D. 100 mL `H_(2)` and 200 mL `NH_(3)` |
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Answer» Correct Answer - A `N_(2)(g) + 3H_(2) (g) hArr 2 NH_(3) (g)` If the quantity of `N_(2) (g)` reacted is 100 mL `therefore` Thequantiy of `H_(2) (g)` is three times, 300 mL and `NH_(3)` produced = 200 mL |
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