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In the synthesis of sodium carbonate, the recovery of ammonia is done by treating NH_(4)Clwith Ca(OH)_(2). The by-product obtained in this process is |
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Answer» `CaCl_(2)` `NH_(3)+H_(2)O+underset("Ammonium bicarbonate")(CO_(2) to NH_(4)HCO_(3))` `NaCl +NH_(4)HCO_(3) underset("Sodium bicarbone")(toNaHCO_(2)darr)+NH_(4)Cl` `2NaHCO_(3)overset(Delta)to underset("Sodium carbone")(Na_(2)CO_(3))+H_(2)O+CO_(2)` `NH_(3)` is recovered from `NH_(4)HCO_(3)` and `NH_(4)Cl` and in this process `CaCl_(2)` is FORMED as a by product ACCORDING to the following reactions: `NH_(4)HCO_(3)overset("heat")to NH_(3)+H_(2)O+CO_(2)` `underset("chloride")underset("Ammonium")(2NH_(4)Cl)+Ca(OH)_(2)tounderset("Ammonia")(2NH_(3))+underset("chloride")underset("Calcium")(CaCl_(2))+2H_(2)O` |
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