1.

In the system shown in figure m_(1)gtm_(2). System is held at rest by thread BC. Just after the thread BC is burnt.

Answer»

ACCELERATION of `m_(1)` will be equal to zero
acceleration of `m_(2)` will be downwards
magnitude of acceleration of two BLOCKS will be non-zero and unequal
magnitude of acceleration of both the blocks will be `((m_(1)-m_(2))/(m_(1)+m_(2)))g`

ANSWER :A


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