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In the time taken by the projectile to reach from `A` to `B` is `t`. Then the distance `AB` is equal to. .A. `(ut)/sqrt3`B. `sqrt3ut/2`C. `sqrt3ut`D. `2ut` |
Answer» Correct Answer - A `u_(x)=ucostheta=ucos60^(@)` `x=AC=u_(x).t` , from figure `cos 30^(@)=(AC)/(AB)` |
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