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In the two gaseous equilibria (i) and (ii) , at a certain temperature, `(i) SO_(2)(g) +1//2 O_(2)(g) hArr SO_(3)(g) ....K_(1)` `(ii) 2SO_(3)(g) hArr 2SO_(2)(g) +O_(2)(g) .....K_(2)` If `K_(1) `is `4 xx 10^(-3)` then `K_(2)` will beA. `8.0 xx 10^(-3)`B. `16.0 xx 10^(-6)`C. `6.25 xx 10^(4)`D. `6.25 xx 10^(8)` |
Answer» Correct Answer - C For the given reactions `K_(2)=(1)/((K_(1))^(2))` Thus `K_(2)=(1)/((4 xx 10^(-3))^(2))=6.25 xx 10^(4)` |
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