1.

In the usual notation the value of DeltaV is equal to

Answer»

`DELTA-NABLA`
`Delta+nabla`
`Delta-nabla`
None of these

Solution : `"Now, Delta nablaf(x)=Delta[F(x)-f(x-h)]`
`=Deltaf(x)-Deltaf(x-h)`
`=Deltaf(x)-[f(x)-f(x-h)]`
`=Deltaf(x)-nablaf(x)`
`therefore Delta nabla=Delta -nabla`


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