In this reaction CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) initially [CO]=0.1 M and at equilibrium [CO]=0.067 M so, if K_c=4.24 than what will be the value of K_p ?

In this reaction CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) initi

1.	In this reaction CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) initially [CO]=0.1 M and at equilibrium [CO]=0.067 M so, if K_c=4.24 than what will be the value of K_p ?
Answer» Solution :`K_p=K_c=4.24` as `Deltan_((G))=0,K_p = (K_c)(RT)^(Deltan)` `therefore K_p=K_c`