In this reaction CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) initially [CO]=0.1 M and at equilibrium [CO]=0.067 M so, in this reaction will K_c gt 0 or K_c lt 0 ?

In this reaction CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) initi

1.	In this reaction CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g)) initially [CO]=0.1 M and at equilibrium [CO]=0.067 M so, in this reaction will K_c gt 0 or K_c lt 0 ?
Answer» Solution :The REACTION is FORWARD because REACTANT is DECREASES. If the reaction is forward `K_c gt 0` and positive.