In transforming 0.01 mole of PbS to PbSO_(4), the volume of 10 volume H_(2)O_(2) required will be :

In transforming 0.01 mole of PbS to PbSO_(4), the volume of 10 volume

1.	In transforming 0.01 mole of PbS to PbSO_(4), the volume of 10 volume H_(2)O_(2) required will be :
Answer» 11.2 mL 22.4 mL 33.6 mL 44.8 mL Solution :`PbS+4H_(2)O_(2) to PbSO_(4)+4H_(2)O` 0.04 mole of `H_(2)O_(2)` is required to REACT with 0.01 mole PbS. Molarity of `H_(2)O_(2)` may be calculated as, Volume strength = Molarity `xx 11.2` `10= M xx 11.2` M=0.892 NUMBER of MOLES`=(MV)/(1000)` `0.04 =(0.892xxV)/(1000)` V=44.8 mL