In transforming 0.01 mole of PbS to PbSO_(4) , the volume of '10 volume' H_(2)O_(2) required will be

In transforming 0.01 mole of PbS to PbSO_(4) , the volume of '10 volum

1.	In transforming 0.01 mole of PbS to PbSO_(4) , the volume of '10 volume' H_(2)O_(2) required will be
Answer» 11.2 mL 22.4 mL 33.6 mL 44.8 mL SOLUTION :`underset(0.01 "mole")(PBS) + underset(0.04 "mole")(4H_(2)O_(2)) to PbSO_(4) + 4H_(2)O` `underset(0.04 "mole")(4H_(2)O_(2)) to 4H_(2)O + underset(0.02xx22400 mL "at N.T.P.")(2O_(2))` Vol of `O_(2)` at N.T.P. `=0.02xx22400` `=448` mL `THEREFORE` Volume of 10 volume `H_(2)O_(2)` solution `=448//10=44.8` mL.