In triangle ABC; ∠ A = 600, ∠ C = 400 and bisector of angle ABC meets side AC at point P. Show that BP= CP.

In triangle ABC; ∠ A = 600, ∠ C = 400 and bisector of angle ABC me

1.	In triangle ABC; ∠ A = 600, ∠ C = 400 and bisector of angle ABC meets side AC at point P. Show that BP= CP.
Answer» In triangle ABC; $∠$ A = $60^{0}$ , $∠$ C = $40^{0}$ and bisector of angle ABC meets side AC at point P. Show that BP= CP.