InterviewSolution
Saved Bookmarks
| 1. |
In triangle ABC, AD is prependicular to BC and DE is perpendicular to AB |
|
Answer» `{:(a,b,c,d),(p,r,Q,q):}` a. Area of `DeltaADB = (1)/(2) AD XX BD` `= (1)/(2) c sin B xx c COS B` `= (c^(2))/(4) sin 2B` b. Area of `DeltaADC = (1)/(2) AD xx CD` `= (1)/(2) b sin C xx b cos C = (b^(2))/(4) sin 2C` c. Area of `DELTAADE = (1)/(2) AE xx DE` `= (1)/(2) AD cos ((pi)/(2) - B) AD sin ((pi)/(2) - B)` `= (1)/(4) AD^(2) sin 2B` `= (1)/(4) c^(2) sin^(2) B sin 2B` d. Area of `DeltaBDE = (1)/(2) BE xx DE` `= (1)/(2) BD cos B xx AD sin ((pi)/(2) -B)` `= (1)/(2) c cos B cos B xx c sin B cos B` `= (1)/(4) c^(2) cos^(2) B sin 2B` |
|