In triangle ABC; angle ABC = 900 and P is a point on AC such that ∠ PBC = ∠ PCB. Show that : BP = CP.

In triangle ABC; angle ABC = 900 and P is a point on AC such that ∠

1.	In triangle ABC; angle ABC = 900 and P is a point on AC such that ∠ PBC = ∠ PCB. Show that : BP = CP.
Answer» In triangle ABC; angle ABC = $90^{0}$ and P is a point on AC such that $∠$ PBC = $∠$ PCB. Show that : BP = CP.