1.

In triangle ABC, $DE\parallel $ where D is a point on AB and E is a point on AC. DE divides the area of $\triangle ABC$ into two equal parts. Then DB:AB is equal to1). $\sqrt{2}:(\sqrt{2}+1)$2). $\sqrt{2}:(\sqrt{2}-1)$3). $(\sqrt{2}-1):\sqrt{2}$4). $(\sqrt{2}+1):\sqrt{2}$

Answer»

$\SQRT{2}:(\sqrt{2}-1)$ is the ANSWER



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