In triangle abc\'E is the mid point of median AD show that area(BED)=1

1.	In triangle abc\'E is the mid point of median AD show that area(BED)=1/4 area(ABC)
Answer» AD is median so,ar ({tex}\\triangle{/tex}ABD) =\xa0{tex}\\frac{1}{2}{/tex}ar({tex}\\triangle{/tex}ABC) ...(i)BE is median so,ar ({tex}\\triangle{/tex}BED) =\xa0{tex}\\frac{1}{2}{/tex}ar (ABD) ... (ii)From (i) & (ii)ar ({tex}\\triangle{/tex}BED) =\xa0{tex}\\frac{1}{4}{/tex}ar ({tex}\\triangle{/tex}ABC)Hence, Proved

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