In triangle ABC, `R (b + c) = a sqrt(bc)`, where R is the circumradius of the triangle. Then the triangle isA. isosceles but not rightB. right but not isoscelesC. right isoscelesD. equilateral

In triangle ABC, `R (b + c) = a sqrt(bc)`, where R is the circumradius

1.	In triangle ABC, `R (b + c) = a sqrt(bc)`, where R is the circumradius of the triangle. Then the triangle isA. isosceles but not rightB. right but not isoscelesC. right isoscelesD. equilateral
Answer» Correct Answer - C `R(b +c) = a sqrt(bc) = 2R sin A sqrt(bc)` `:. sin A = (b +c)/(2sqrt(bc))` Now `sin A le 1` `rArr (b + c)/(2sqrt(bc)) le 1` or `(sqrtb - sqrtc)^(2) le 0` or `b = c` `rArr sin A = 1` `rArr A = 90^(@) and b = c` Hence, the triangle is right isosceles.

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In triangle ABC, `R (b + c) = a sqrt(bc)`, where R is the circumradius of the triangle. Then the triangle isA. isosceles but not rightB. right but not isoscelesC. right isoscelesD. equilateral

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