in triangle ABC, sin A cos Ba. right angled1/4 and 3 tan A tan B, then – InterviewSolution

1.	in triangle ABC, sin A cos Ba. right angled1/4 and 3 tan A tan B, then the triangle ish equilaterale. isoscelesd none of
Answer» SinA* SInB= 1/4meanssinA= 1/2cosB= 1/2angle A= 30°angle B= 60°so it would be an 90° at angle C

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