in triangle PQR ,angle Q=90 degree ,sin R=3/5 find sec P – InterviewSolution

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1.

in triangle PQR ,angle Q=90 degree ,sin R=3/5 find sec P

Answer»

cos(P)= cos (90°-R)= sin(R)= 3/5

therefore, sec(P)= 1/cos(P)= 5/3

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