1.

In triangleABC, sin((A)/(2))sin((B)/(2))sin((C)/(2))=

Answer»

`(A(TRIANGLEABC))/(ABC)`
`(A(triangleABC))/(ABCS)`
`(A(triangleABC)^(2))/(abc)`
`(A(triangleABC)^(2))/(abcs)`

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