In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles w

1.	In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if(A) BC = EF (B) AC = DE (C) AC = EF (D) BC = DE
Answer» (B) AC = DE Given, in ΔABC and ΔDEF, AB = DF and ∠A = ∠D We know that, two triangles will be congruent by ASA rule, if two angles and the included side of one triangle are equal to the two angles and the included side of other triangle. ∴ AC = DE

In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if(A) BC = EF (B) AC = DE (C) AC = EF (D) BC = DE

Answer»

(B) AC = DE

Given, in ΔABC and ΔDEF, AB = DF and ∠A = ∠D

We know that, two triangles will be congruent by ASA rule, if two angles and the included side of one triangle are equal to the two angles and the included side of other triangle.

∴ AC = DE

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In triangles ABC and DEF, AB = FD and ∠A = ∠D. The two triangles will be congruent by SAS axiom if(A) BC = EF (B) AC = DE (C) AC = EF (D) BC = DE

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