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In van der Waal's equations (P+a/(V^(2)))(V-b)=RT, what are the dimensions of the constants a and b? |
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Answer» Solution :`a/(V^(2))` is added to P. So `a/(V^(2))` must have the dimensions of pressure P. B is subrtracted form V. So b must have the dimensions of volume V. Dimensions of `a/(V^(2))=` Dimensions of Pressure DIMENSIONAL FORMULA of `a=[ML^(-1)T^(-2)][L^(3)]^(2)=[ML^(5)T^(-2)]` Dimensional formula of `b=[L^(3)]` |
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