In which case is the number of molecules of water maximum?A. (a)18 mL of waterB. (b)0.18 g of waterC. (c )0.00224 L of water vapour at 1 atm and 273 KD. (d)`10^(-3)` mol of water

In which case is the number of molecules of water maximum?A. (a)18 mL

1.	In which case is the number of molecules of water maximum?A. (a)18 mL of waterB. (b)0.18 g of waterC. (c )0.00224 L of water vapour at 1 atm and 273 KD. (d)`10^(-3)` mol of water
Answer» Correct Answer - d (a) `18 mL` water As `d_(H_(2)O)=1 g//mL` So `W_(H_(2)O)=18 g` `n_(H_(2)O)=18/18=1` molecules `=1xxN_(A)` (b) `0.18` g of water `n_(H_(2)O)=0.18/18=0.01` `("molecules")_(H_(2)O)=0.01 xxN_(A)` (c ) `(V_(H_(2)O(g)))_(STP)=0.00224 L` `n_(H_(2)O)=V/22.4=0.00224/22.4=0.0001` molecules`=0.0001xxNA` (d) `n_(H2O)=10^(-3)` `("molecules")_(H2O)=10^(-3)xxN_(A)`

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In which case is the number of molecules of water maximum?A. (a)18 mL of waterB. (b)0.18 g of waterC. (c )0.00224 L of water vapour at 1 atm and 273 KD. (d)`10^(-3)` mol of water

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