In which equilibrium it will K_p=K_c. (i)CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g)) (ii)2HI_((g)) hArr H_(2(g)) + I_(2(g)) (iii)N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) (iv)C_((s)) + O_(2(g)) hArr CO_(2(g)) (v)PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) (vi)CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g))

In which equilibrium it will K_p=K_c. (i)CaCO_(3(s)) hArr CaO_((s)) +

1.	In which equilibrium it will K_p=K_c. (i)CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g)) (ii)2HI_((g)) hArr H_(2(g)) + I_(2(g)) (iii)N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) (iv)C_((s)) + O_(2(g)) hArr CO_(2(g)) (v)PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) (vi)CO_((g)) + H_2O_((g)) hArr CO_(2(g)) + H_(2(g))
Answer» Solution :In (II),(iv), and (vi), `K_p=K_c` because `Deltan_((G))`=ZERO