In which fo the following has the oxidation number of oxygen been arragned in increasing order ?A. `KO_2 lt OF_2 lt O_3 lt BaO_2`B. `BaO_2 lt KO_2 lt O_3 lt OF_2`C. `BaO_2 lt O_3 lt OF_2 lt KO_2`D. `OF_2 lt KO_2 lt BaO_2 lt O_3`

In which fo the following has the oxidation number of oxygen been arra

1.	In which fo the following has the oxidation number of oxygen been arragned in increasing order ?A. `KO_2 lt OF_2 lt O_3 lt BaO_2`B. `BaO_2 lt KO_2 lt O_3 lt OF_2`C. `BaO_2 lt O_3 lt OF_2 lt KO_2`D. `OF_2 lt KO_2 lt BaO_2 lt O_3`
Answer» Correct Answer - B Let x be the oxidation number (O.N.) of O atom in a given compound: O.N. of O in ` BaO_2 rArr (+2) +2x rArr =0 rArr x=- 1` O.N of O in `KO_2 rArr (+1) + 2x =0 rArr x=- 1//2` O.N. of O in `O_3 rArr 0` (Free state or uncombined state ) O.N. of O in ` OF_2 rArr x+ 2(-1) =0 rArr x= +2` `:. Baoverset(-1)(O_(2)) lt Koverset(-1//2)(O_(2)) lt overset(0)(O_(2)) lt overset(+2)(OF_(2))`

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In which fo the following has the oxidation number of oxygen been arragned in increasing order ?A. `KO_2 lt OF_2 lt O_3 lt BaO_2`B. `BaO_2 lt KO_2 lt O_3 lt OF_2`C. `BaO_2 lt O_3 lt OF_2 lt KO_2`D. `OF_2 lt KO_2 lt BaO_2 lt O_3`

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