1.

In which of the following compounds, an element exhibits two different oxidation states ?

Answer»

`NH_(4)OH`
`NH_(4)NO_(3)`
`N_(2)H_(4)`
`N_(3)H`

Solution :`NH_(4)NO_(3)toNH_(4)^(+)+NO_(3)^(-)`
OXIDATION NUMBER in `NH_(4)^(+)` is -3.
Oxidation number in `NO_(3)^(-)` is +5.


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