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In which of the following compounds the percentage of carbon atom is highest ? |
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Answer» `CH_(3)-CH_(2)-CH_(3)` (A) `CH_(3)CH_(2)CH_(3) -= C_(3)H_(8)` `= 3 (C) + 8 (H)` `= 3 (12) + 8 (1)` `= 36 + 8` `= 44 g* "mol"^(-1)` and36 g Carbon in it. % C `= (100xx36)/(44) = 81.818 % C`......(A) `underset("OH")underset("|")(CH_(3)+CH-CH_(3)-=C_(3)H_(8)O)` `3(C) + 8(H) + 1(16)` `= 36+8 + 16` `= 60 g "mol"^(-1)` and 36 g C in it. `% C = (100xx36)/(60) = 60% C `.........(B) (C) `C_(12)H_(22)O_(11)` `= 12(C) + 22(H) +11(O)` `= 12(12)+22(1) + 11(16)` `= 144+22+176` `= 342g* "mol"^(-1)` and144 g C in it. `% C = (144xx100)/(342) = 42.105% C`......(C) (D) `CH_(3)COOH -= C_(2)H_(4)O_(2)` `=2(C)+4(H) +2(O)` `=2(12)+4(1)+2(16)` `= 24+4+32` `= 60 g "mol"^(-1)`and `24 g` C in it. `%C = (24)/(60) XX 100 = 40% C `.......(D) |
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