Saved Bookmarks
| 1. |
In which of the following molecules, sigma 2p_(z) molecular orbital is filled after pi 2p_(x) and pi 2p_(y) molecular orbitals ? |
|
Answer» `O_(2)` Total number of electrons present in `N_(2)` molecule is 14. The electronic configuration of `N_(2)`molecule will be , `sigma 1s^(2), sigma^(**) , sigma 2s^(2) ,sigma^(**) 2s^(2) , pi 2p_(x)^(2) = pi 2p_(y)^(2) , pi 2p_(z)^(2)` The increasing order of energies of various molecular orbitals for `O_(2) and F_(2)` is given below `sigma 1s lt sigma^(**) lt sigma 2s lt sigma^(**) 2s lt sigma 2p_(z) lt (pi 2p_(x) = pi 2p_(y)) lt (pi^(**) 2p_(x) = pi^(**) 2p_(y) ) lt sigma^(**) 2p_(z)` HOWEVER, this sequence of energy levels of MO is not CORRECT for the remaining MOLECULES such as `Li_(2) , Be_(2) , B_(2) , C_(2) and N_(2).` for these molecules, the increasing order of energies of various MO is `sigma 1s lt sigma^(**) 1s lt sigma 2s lt sigma^(**) 2s lt (pi 2p_(x) = pi 2p_(y)) lt sigma 2p_(z) lt (pi^(**) 2p_(x) = pi^(**) 2p_(y)) sigma 2p_(z)` |
|