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In which of the following orbitals , the sum of `( n+1)` value is lowest ? `4s, 3d, 4p` |
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Answer» `4s rarr n = 4, l = 0, ( n+l) =4` `3d rarr n=3,l= 2, ( n+l)= 5` `4p rarr n = 4 , l= 1, ( n+1) = 5` Therefore, 4s- orbital is lowest in energy . |
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