1.

In which of the following orbitals , the sum of `( n+1)` value is lowest ? `4s, 3d, 4p`

Answer» `4s rarr n = 4, l = 0, ( n+l) =4`
`3d rarr n=3,l= 2, ( n+l)= 5`
`4p rarr n = 4 , l= 1, ( n+1) = 5`
Therefore, 4s- orbital is lowest in energy .


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