1.

In which of the following pairs of compounds, carbon atom is not sp^(2) hybmridised?

Answer»

butanal, butan-2-ol
butanoic, acid, butanone
pentanamide, pent-1-ene
2-methyl propana-2-ol, butan-2-ol

Solution :Bu tanal
`CH_(3)-CH_(2)-CH_(2)-underset(underset(sp^(2))(uarr))overset(overset(O)(||))(C )-H`
Bu tane-2-ol `CH_(3)-CH_(2)-overset(overset(OH)(|))(C )H-CH_(3)` All carbon `sp^(3)`
(B) butanoic acid `CH_(3) CH_(2)CH_(2)- underset(underset(sp^(2))(uarr))overset(overset(O)(||))(C )-OH`
butanone `CH_(3)-underset(underset(sp^(2))(uarr))overset(overset(O)(||))(C )-CH_(2)-CH_(3)`
(C )PENTAN AMIDE `CH_(3)CH_(2)CH_(2)CH_(2)- underset(underset(sp^(2))(uarr))overset(overset(O)(||))(C )-NH_(2)`
pent-1-ene `CH_(3)CH_(2)CH_(2) underset(underset(sp^(2))(uarr))(CH)= underset(underset(sp^(2))(uarr))(CH_(2))`
(D) 2-methyl propan-2-ol `CH_(3)- underset(underset(OH)(|))overset(overset(CH_(3))(|))(C )-CH_(3)` All CARBONS are `sp^(3)`
butane-2-ol `CH_(3)CH_(2)- overset(overset(OH)(|))(C )HCH_(3)` All carbons are `sp^(3)`


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