1.

In which of the following pairs, the ions are isoelectronic ?

Answer»

`Na^(+), MG^^(2+)`
`Al^(3+), O^(-)`
`Na^(+), O^(2-)`
`N^(3), Cl^(-)`

Solution :`Na^(+) = 11 -1 = 10 e^(-), Mg^(2+) = 12 -2 = 10 e^(-)`. THUS, they have same no. of electrons
`Al^(3+) = 13 -3 = 10 e^(-), Q^(2-) = 8 + 2 = 10 e^(-)`. They have same no. of electrons
`N^(3-) = 7 + 3 = 10 e^(-), Cl^(-) = 17 + 1 = 18 e^(-)`. They do not have same no. of electrons


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