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In which ratio is the line joining (1, 3) and (2, 7) divided by 3x + y = 9 |
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Answer» Let the point (x,y) divides AB in the ratio k:1. By section formula, x = (2k+1)/(k+1) , y = (7k+3)/(k+1) Now, this point also lies on the given line so it would satisfy the equation 3x+y-9=0 Therefore, 3(2k+1) + (7k+3) -9(k+1) = 0 k = 3/4 Hence, the required ratio is 3:4. |
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