In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be placed in front of the upper slit `S_1` so that the central maximum now lies at a point where 5th bright fringe was lying earlier (before inserting the slab). Wavelength of light used is `5000 Å`.

In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be

1.	In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be placed in front of the upper slit `S_1` so that the central maximum now lies at a point where 5th bright fringe was lying earlier (before inserting the slab). Wavelength of light used is `5000 Å`.
Answer» Correct Answer - 50,000 `Å` According to the question, shift = 5 (fringe width) `:. ((mu -1)tD)/(d) = (5 lambda D)/(d)` `:. t = (5 lambda)/(mu - 1) = (25000)/(15.1) = 50,000 Å`

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In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be placed in front of the upper slit `S_1` so that the central maximum now lies at a point where 5th bright fringe was lying earlier (before inserting the slab). Wavelength of light used is `5000 Å`.

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