In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be placed in front of the upper slit `S_1` so that the central maximum now lies at a point where 5th bright fringe was lying earlier (before inserting the slab). Wavelength of light used is `5000 Å`.A. `5 xx 10^(-6)m`B. `3 xx 10^(-6)m`C. `10 xx 10^(-6) m`D. `5 xx 10^(-5) m`

In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be

1.	In YDSE, find the thickness of a glass slab `(mu=1.5)` which should be placed in front of the upper slit `S_1` so that the central maximum now lies at a point where 5th bright fringe was lying earlier (before inserting the slab). Wavelength of light used is `5000 Å`.A. `5 xx 10^(-6)m`B. `3 xx 10^(-6)m`C. `10 xx 10^(-6) m`D. `5 xx 10^(-5) m`
Answer» Correct Answer - a According to the question, shift = 5 fringe widths `implies ((mu - 1)t D)/(d) = (5 lambda D)/(d)` `:.t = (5 lambda)/(mu - 1) = (25000)/(1.5 - 1) = 50,000 Å`

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