

InterviewSolution
Saved Bookmarks
1. |
In YDSE shown in figure a parallel beam of light is incident on the slits from a medium of refractive index `n_(1)`. The wavelength of light in this medium is `lambda_(1)`. A transparent of thickness t and refractive index `n_(3)` is put in front of one slit. The medium between the screen and the plane of the slits is `n_(2)`. The phase difference between the light waves reaching point O (symmetrical, relative to the slits) is A. `(2pi)/(n_(1)lambda_(1))(n_(3)-n_(2))t`B. `(2pi)/(lambda_(1))(n_(3)-n_(2))t`C. `(2pin_(1))/(n_(2)lambda_(1))((n_(3))/(n_(2))-1)t`D. `(2pin_(1))/(lambda_(1))(n_(3)-n_(1))t` |
Answer» Correct Answer - A |
|