1.

In Young’s double slit experiment, the intensity at centre of screen is I. If one of the slit is closed, the intensity at centre now will be(a) I(b) \(\frac{l}{3}\)(c) \(\frac{l}{4}\)(d) \(\frac{l}{2}\)

Answer»

Answer is :  (c) \(\frac{l}{4}\)

If I0 is the intensity after closing one slit, then it satisfies

I∝ a2

(where, a = amplitude of light wave)

When both slits open, then intensity

∴ l ∝ (2a)2 = 4a2

⇒ l0\(\frac{l}{4}\)



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