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In Young’s double slit experiment, the intensity at centre of screen is I. If one of the slit is closed, the intensity at centre now will be(a) I(b) \(\frac{l}{3}\)(c) \(\frac{l}{4}\)(d) \(\frac{l}{2}\) |
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Answer» Answer is : (c) \(\frac{l}{4}\) If I0 is the intensity after closing one slit, then it satisfies I0 ∝ a2 (where, a = amplitude of light wave) When both slits open, then intensity ∴ l ∝ (2a)2 = 4a2 ⇒ l0 = \(\frac{l}{4}\) |
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