InterviewSolution
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InterviewSolution
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Increasing order of ionic size : `N^(3-),Na^(+),F^(-),O^(2-),Mg^(2+)`A. `Mg^(2+ )lt Na^(+) ltF^(-) lt O^(2-) lt N^(3-)`B. `Na^(+) lt Mg^(2+) lt F^(-) lt O^(2-) lt N^(3-)`C. `N^(3-) lt O^(2-) ltF^(-) lt Na^(+) lt Mg^(2+)`D. `F^(-)ltN^(3-) lt O^(2-) lt Mg^(2+) lt Na^(+)` |
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Answer» Correct Answer - A `N^(3+), Na^(+), F^(-) , O^(2-) and Mg^(2+)` are all isoelectronic ions. In such ions more the nuclear charge (or atomic number) smaller is the ion. Thus, the correct order of ionic radii of `N^(3-)` (Z= 7 ), `Na^+` (Z=11), `F^-` (Z = 19), `O^(2-)` (Z =8) and `Mg^(2+)` (Z= 12) is `Mg^(2+) lt Na^(+) lt F^(-) lt O^(2-) lt N^(3-)` |
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