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inder wrien divided by Ir¡2)lind the valuby' (sby irhe polynoindal >3 +2x5x-7 when aided byT2), lind the value of k.remaindet a. ithe polynomini r3 + a 12x + 6 hen2p +4 6, then find the valye ni, 12/1~vesdivided by ( 2) leaves thedgd by (x 2) and remainder |
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Answer» R1 = x3+2x2-5kx-7R2 = x3+kx2-12x+6 for R1 x = -1 and for R2 x = 2 put the values of x R1 = (-1)^3+2(-1)^2-5k(-1) -7R1 = -1 +2 + 5k -7p = 5k - 6 R2 = (2)^3+k(2)^2-12(2)+6R2 = 8 + 4k -24 +6q = 4k - 10 2p+q = 6 2(5k-6)+(4k-10) = 6 10k-12+4k-10 = 6 14k = 6+12+10 k = 28/14 k = 2 Like my answer if you find it useful! |
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